Kepler's Second Law
An imaginary line between a planet and the Sun will sweep out the same area in equal periods
of time.
This law is equivalent to the present-day Law of Conservation of Angular Momentum. The
classic example of this latter law is an ice-skater who rotates faster when (s)he draws in
initially-outstretched arms.
In the above diagram, the two shaded regions have identical areas.
The period of time taken for the planet to travel
between A and B is equivalent to the period of time it takes to travel between
C and D.
The path between C and D could represent the path of our Earth at some time
during our Summer in Britain.
The path between A and B could represent the Earth's path at some time during
Australia's Summmer. This ellipse would be highly distorted in comparison with the Earth's
true orbital shape, but the general ideas can be seen. All other things being equal, our
Summers
would be cooler than Australia's but would last longer. These effects are modified by the
atmosphere - note that Midsummer's Day in Britain is around June 21, but atmospheric effects
ensure that the hottest month is usually August.
Kepler's Third Law
The square of the period of a planet is equal to the cube of its average distance from
the Sun.
This is a very simplified version of the law. In its full version it is applied to
binary systems. We have carried out two main simplifications - thus
- Strictly speaking, a Sun/planet system is a binary system rotating about the common
center of the system. The common center of the system is so close to the center of the Sun
that we
can approximate the situation by considering the Sun to be static
and ignore the planet's mass as being negligible in comparison
with the Sun's. This will simplify the original equation.
- By selecting the inserted values to be in specific units
(namely years and Astronomical Units), we can eliminate any
constants in the full equation, and state the law as we have done at the top.
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In mathematical form, the law is now stated as
τ2 = a3
where
τ
is the period of a planet
a
is the average distance of the planet from the Sun
Remember, τ
must be in years and
a
must be in AUs (Astronomical Units).
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Quick Quiz
a)
What would be the orbital period of a planet with a mean orbit radius of 8 AU ?
b)
The mean distance of Mars from the Sun is 1.5 AU. Calculate its orbital period.
c) A satellite orbits a planet in 18 hours. It is moved to a new orbit with a period of 4.5 hours.
The orbital radius decreases by what factor ?
d)
e)
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For a circular orbit, at a height of 200 km above the Earth's surface, the speed will be 7.8 km/s. At 36 000 km, it will be 3.1 km/s. Mir was put into orbit at 350 km. with no eccentricity.